What I knew about area of regular polygons before watching the video was that I knew how to find the area of triangles, circles, etc., but not the way that the video explains it. This is all I knew about before watching the video.
What I learned about after watching the video was about how to find the area of an equilateral triangle and how to find the area of a regular polygon. To find the area of an equilateral triangle you use the equation Area equals one half times side squared times the square root of three (A=½{s^2} 
<!--[endif]-->). To find the area of a regular polygon you use the equation Area equals one half time apothem times perimeter (A=½aP). The apothem of a regular polygon is the measure of the line that goes from the center of the polygon to the middle of a side. To find the perimeter of a regular polygon you divide 360 and the number of sides the polygon has, and then you use either cosine, sine, or tangent to find the half of the side length. Lastly, you times that number by two to get the whole side length and times that by the number of sides you have. You use these two equations to find the area of equilateral triangles and the area of a regular polygon. This is everything that I learned about in the video.
<!--[endif]-->). To find the area of a regular polygon you use the equation Area equals one half time apothem times perimeter (A=½aP). The apothem of a regular polygon is the measure of the line that goes from the center of the polygon to the middle of a side. To find the perimeter of a regular polygon you divide 360 and the number of sides the polygon has, and then you use either cosine, sine, or tangent to find the half of the side length. Lastly, you times that number by two to get the whole side length and times that by the number of sides you have. You use these two equations to find the area of equilateral triangles and the area of a regular polygon. This is everything that I learned about in the video.Word Count: 234
Questions:
Questions:
I commented on Kollin Heimke's Blog and Rebecca Phipps's blog.
Okay, for the first question you want to solve for the the top angle and since we have a pentagon we would take 360 and then divide it by 5 so we would get 72 and then from there since we just solved for the equilateral triangle we would divide it by 2 to get 36 so we are then able to use trig to solve for a and p so for so for p you would take 4cos36=x and then for a you get 4 sin36=y so we then plug it into our equation so you get the area=1/2(4cos36)(40sin36) so for you final answer you get 38.042
ReplyDeleteFor your second question you have to take 360/5=72 to get the angle measures. Then you have x=7cos36, and y=7sin36. You would times the y by two to get one side=14sin36. You would times that by five and then plug it into the equation to get 1/2(70sin36)(7cos36). You would simplify that to get a final answer of 116.5m2.
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